Digital Logic Circuits and Discrete Mathematical Structures Topic Wise Pyq

71. Full form of EBCDIC:
EBCDIC का full form क्या है?
(DSSSB TGT 2021)
A. External Binary...
B. External Bit...
C. External Bit Decimal...
D. Extended Binary Coded Decimal Interchange Code

Correct Answer: D

Explanation (EN): Full form = Extended Binary Coded Decimal Interchange Code

Explanation (HI): पूरा नाम = Extended Binary Coded Decimal Interchange Code

72. (1715)₁₀ in base 12:
(1715)₁₀ को base 12 में बदलें
(DSSSB TGT 2021)
A. BAA
B. ABA
C. BCB
D. BAB

Correct Answer: D

Explanation (EN): 1715 ÷ 12 → result = BAB

Explanation (HI): 1715 को 12 से divide करने पर → BAB

73. Range of symbols in base b:
Base b में symbols की range क्या होती है?
(DSSSB TGT 2021)
A. 0 to b
B. 1 to b
C. 0 to (b−1)
D. 1 to (b−1)

Correct Answer: C

Explanation (EN): Digits range from 0 to b−1

Explanation (HI): Digits 0 से (b−1) तक होते हैं

74. Bits required to represent 0 to (2ⁿ−1):
0 से 2ⁿ−1 तक संख्या दिखाने के लिए कितने bits चाहिए?
(DSSSB TGT 2021)
A. n
B. n−1
C. n²−1
D. n+1

Correct Answer: A

Explanation (EN): n bits represent 2ⁿ values

Explanation (HI): n bits → 2ⁿ संख्याएँ

75. Binary equivalent of (25.625)₁₀:
(25.625)₁₀ का binary equivalent क्या है?
(DSSSB PGT 2021)
A. 10001.11
B. 11101.001
C. 11011.1
D. 11001.101

Correct Answer: D

Explanation (EN): 25 = 11001 0.625 = 0.101 Final = 11001.101

Explanation (HI): 25 = 11001 0.625 = 0.101 अंतिम उत्तर = 11001.101

76. What is the minuend in the following subtraction: subtract (011100)₂ from (1011100)₂?
निम्न subtraction में minuend क्या है: (011100)₂ को (1011100)₂ में से घटाइए?
(DSSSB PGT C.S. M/F 11.07.2021)
A. (111000)₂
B. (1011100)₂
C. (100100)₂
D. (100101)₂

Correct Answer: B

Explanation (EN): In subtraction, the minuend is the number from which another number is subtracted. Here, (011100)₂ is subtracted from (1011100)₂. So, the minuend is (1011100)₂.

Explanation (HI): Subtraction में minuend वह संख्या होती है जिसमें से दूसरी संख्या घटाई जाती है। यहाँ (011100)₂ को (1011100)₂ में से घटाया जा रहा है। अतः minuend (1011100)₂ है। ________________________________________

77. What is the product of (10110)₂ and (10011)₂?
(10110)₂ तथा (10011)₂ का गुणनफल क्या है?
(DSSSB PGT C.S. M/F 11.07.2021)
A. (110110101)₂
B. (110100010)₂
C. (110100001)₂
D. (110100100)₂

Correct Answer: B

Explanation (EN): Convert to decimal: (10110)₂ = 22 (10011)₂ = 19 Now multiply: 22 × 19 = 418 Convert 418 to binary: 418 = 110100010₂

Explanation (HI): पहले decimal में बदलते हैं: (10110)₂ = 22 (10011)₂ = 19 अब गुणा करें: 22 × 19 = 418 418 का binary रूप = 110100010₂

78. What is the value of (3564)₈ + (323232)₄ ?
(3564)₈ + (323232)₄ का मान क्या है?
(DSSSB PGT C.S. M/F 11.07.2021)
A. (1E62)₁₆
B. (1662)₁₆
C. (1762)₁₆
D. (1562)₁₆

Correct Answer: B

Explanation (EN): Convert (3564)₈ to decimal: = 3×8³ + 5×8² + 6×8 + 4 = 1536 + 320 + 48 + 4 = 1908 Convert (323232)₄ to decimal: = 3×4⁵ + 2×4⁴ + 3×4³ + 2×4² + 3×4 + 2 = 3072 + 512 + 192 + 32 + 12 + 2 = 3822 Now add: 1908 + 3822 = 5730 Convert 5730 to hexadecimal: 5730 = 1662₁₆

Explanation (HI): (3564)₈ को decimal में बदलें: = 1908 (323232)₄ को decimal में बदलें: = 3822 अब जोड़ें: 1908 + 3822 = 5730 5730 का hexadecimal रूप = 1662₁₆

79. What is the 2's complement of (−28)₁₀ in 16-bit representation?
16-bit representation में (−28)₁₀ का 2's complement क्या होगा?
(DSSSB PGT C.S. M/F 11.07.2021)
A. 1000000000011100
B. 1111111111100011
C. 1111111111100100
D. 1111111111100101

Correct Answer: C

Explanation (EN): First write +28 in 16 bits: 28 = 0000000000011100 Now take 1's complement: 1111111111100011 Add 1 to get 2's complement: 1111111111100011 + 1 = 1111111111100100

Explanation (HI): पहले +28 को 16-bit में लिखें: 28 = 0000000000011100 अब 1's complement लें: 1111111111100011 अब 1 जोड़ें: 1111111111100011 + 1 = 1111111111100100

80. What is the 6's complement of (1543)₇ ?
(1543)₇ का 6's complement क्या है?
(DSSSB PGT C.S. M/F 11.07.2021)
A. (6132)₇
B. (5132)₇
C. (5123)₇
D. (5432)₇

Correct Answer: C

Explanation (EN): In base 7, the highest digit is 6. So 6's complement is found by subtracting each digit from 6: 6 − 1 = 5 6 − 5 = 1 6 − 4 = 2 6 − 3 = 3 So the 6's complement of (1543)₇ is (5123)₇

Explanation (HI): Base 7 में सबसे बड़ा digit 6 होता है। इसलिए 6's complement निकालने के लिए हर digit को 6 में से घटाते हैं: 6 − 1 = 5 6 − 5 = 1 6 − 4 = 2 6 − 3 = 3 अतः (1543)₇ का 6's complement (5123)₇ है।

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